ksh scripting problem

Does anybody have any idea why this works:

IFS=' '
exec 0< "db/s.d"
while read line
do
set $line
if (($3>0)) && ((${15}<16))
then

And this doesn't?

exec 0< "s.p"
while read line
do
set $line
((++wkcnt))
if (($1>0)) [>0: arithmetic syntax error]
then

The line is getting read correctly as shown if I do a print $1 after the
set.

Actually, since the line in the second case only holds one field,
it should be possible to get away without doing a set, but I was trying
to match the other code.

The first few lines of s.p look like

16.1299990
16.7199990
16.9800000
16.0000000
16.9900000

--
Robert B. Peirce, Venetia, PA 724-941-6883
bob AT peirce-family.com [Mac]
rbp AT cooksonpeirce.com [Office]

Okay. Here's a real puzzle and I don't think it has anything to do with
\r.

This doesn't work. It hangs at the if statement, which doesn't execute.
p=$(echo $line | tr -d '\r')
((++wkcnt))
if ((p>0))

This does work
p=$(echo $line | tr -d '\r')
((++wkcnt))
#
if ((p>0))

As does this
((++wkcnt))
p=$(echo $line | tr -d '\r')
if ((p>0))

You need something after ((++wkcnt)) for if to work and that makes no
sense to me at all.

--
Robert B. Peirce, Venetia, PA 724-941-6883
bob AT peirce-family.com [Mac]
rbp AT cooksonpeirce.com [Office]